m^2/12=m/4+1/3

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Solution for m^2/12=m/4+1/3 equation: 


m in (-oo:+oo)

(m^2)/12 = m/4+1/3 // - m/4+1/3

(m^2)/12-(m/4)-(1/3) = 0

(m^2)/12-(m/4)-1/3 = 0

1/12*m^2-1/4*m-1/3 = 0

DELTA = (-1/4)^2-(-1/3*1/12*4)

DELTA = 25/144

DELTA > 0

m = ((25/144)^(1/2)+1/4)/(1/12*2) or m = (1/4-(25/144)^(1/2))/(1/12*2)

m = 4 or m = -1

m in { -1, 4 }

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